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-16x^2+135x+56=0
a = -16; b = 135; c = +56;
Δ = b2-4ac
Δ = 1352-4·(-16)·56
Δ = 21809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(135)-\sqrt{21809}}{2*-16}=\frac{-135-\sqrt{21809}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(135)+\sqrt{21809}}{2*-16}=\frac{-135+\sqrt{21809}}{-32} $
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